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<DIV>OK, Chuck,</DIV>
<DIV>I think I am getting clued in. </DIV>
<DIV> </DIV>
<DIV>So really more than IR drops due to loads we are talking inductive drops or
increases of voltage V=Ldi/dt depending on increasing or decreasing
current. </DIV>
<DIV> </DIV>
<DIV>So for an instant, when relay opens and current in motor circuit decreases
very rapidly , Scott's ground lead looks like a battery supplying at least
a few volts to the ground wire -- got it.</DIV>
<DIV> </DIV>
<DIV>If per chance it supplied 5 volts, the voltage supply might drop to zero --
assuming no capacitance at processor.</DIV>
<DIV> </DIV>
<DIV>This brings up a question. Could a reasonable capacitor say 10 uF tied to
processor (or real close) protect processor from the bounce?</DIV>
<DIV> </DIV>
<DIV>Ron</DIV>
<DIV> </DIV>
<DIV> </DIV>
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